":{"type":"<nil>","message":"获取token失败: 没有可用的token (request id: 2026032014125166...

报错分析报告

1.错误翻译

原文：Failed to get token: No available token
译文：获取token失败：没有可用的token

2. 原因分析

3.解决方案

import requests
from datetime import datetime, timedelta

class TokenManager:
    def __init__(self):
        self.token = None
        self.expiry = None  # token过期时间

    def get_valid_token(self, auth_url, credentials):
        """获取有效token（自动刷新）"""
        # 检查现有token是否有效
        if self.token and datetime.now() < self.expiry:
            return self.token
        
        # 重新请求token
        try:
            resp = requests.post(auth_url, json=credentials, timeout=10)
            resp.raise_for_status()
            data = resp.json()
            self.token = data["access_token"]  # 根据实际响应字段调整
            # 设置过期时间（假设响应含expires_in秒数）
            self.expiry = datetime.now() + timedelta(seconds=data.get("expires_in", 3600))
            return self.token
        except requests.exceptions.RequestException as e:
            raise Exception(f"获取token失败: {str(e)}") from e

# 使用示例
if __name__ == "__main__":
    auth_config = {
        "auth_url": "https://dmxapi.com/auth/token",
        "credentials": {"client_id": "YOUR_ID", "client_secret": "YOUR_SECRET"}
    }
    token_mgr = TokenManager()
    
    try:
        token = token_mgr.get_valid_token(**auth_config)
        print(f"成功获取token: {token[:8]}...")
    except Exception as e:
        print(f"错误: {e}")

4. 预防措施